Tag: Context Free Languages

Algorithm To Decide Whether CFL Is Finite

Context Free Language-

 

Before you go through this article, make sure that you have gone through the previous article on Context Free Language.

 

We have discussed-

  • Context free language is generated using a context free grammar.
  • Each context free language is accepted by a Pushdown automaton.

 

In this article, we will discuss a decision algorithm of CFL.

 

Algorithm To Decide Whether CFL Is Finite Or Not-

 

For a given CFG, there exists an algorithm to decide whether its language is finite or not.

 

Step-01:

 

Reduce the given grammar completely by-

  • Eliminating ∈ productions
  • Eliminating unit productions
  • Eliminating useless productions

 

Also Watch- How To Reduce Grammar?

 

Step-02:

 

  • Draw a directed graph whose nodes are variables of the given grammar.
  • There exists an edge from node A to node B if there exists a production of the form A → αBβ.

 

Now, following 2 cases are possible-

 

Case-01:

 

  • Directed graph contains a cycle.
  • In this case, language of the given grammar is infinite.

 

Case-02:

 

  • Directed graph does not contain any cycle.
  • In this case, language of the given grammar is finite.

 

Also Read- Algorithm To Decide Whether CFL Is Empty

 

PRACTICE PROBLEMS BASED ON DECIDING WHETHER CFL IS FINITE-

 

Problem-01:

 

Check whether language of the following grammar is finite or not-

S → AB / a

A → BC / b

B → CC / c

 

Solution-

 

Step-01:

 

The given grammar is already completely reduced.

 

Step-02:

 

We will draw a directed graph whose nodes will be S , A , B , C.

 

Now,

  • Due to the production S → AB, directed graph will have edges S → A and S → B.
  • Due to the production A → BC, directed graph will have edges A → B and A → C.
  • Due to the production B → CC, directed graph will have edge B → C.

 

The required directed graph is-

 

 

Clearly,

  • The directed graph does not contain any cycle.
  • Therefore, language of the given grammar is finite.

 

Problem-02:

 

Check whether language of the following grammar is finite or not-

S → XS / b

X → YZ

Y → ab

Z → XY

 

Solution-

 

Step-01:

 

The given grammar is already completely reduced.

 

Step-02:

 

We will draw a directed graph whose nodes will be S , X , Y , Z.

 

Now,

  • Due to the production S → XS / b, directed graph will have edges S → X and S → S.
  • Due to the production X → YZ, directed graph will have edges X → Y and X → Z.
  • Due to the production Z → XY, directed graph will have edges Z → X and Z → Y.

 

The required directed graph is-

 

 

Clearly,

  • The directed graph contain cycles.
  • Therefore, language of the given grammar is infinite.

 

Next Article- CYK Algorithm

 

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Algorithm To Decide Whether CFL Is Empty

Context Free Language-

 

Before you go through this article, make sure that you have gone through the previous article on Context Free Language.

 

We have discussed-

  • Context free language is generated using a context free grammar.
  • Each context free language is accepted by a Pushdown automaton.

 

In this article, we will discuss a decision algorithm of CFL.

 

Algorithm To Decide Whether CFL Is Empty Or Not-

 

If we can not derive any string of terminals from the given grammar,

then its language is called as an Empty Language.

L(G) = ϕ

 

For a given CFG, there exists an algorithm to decide whether its language is empty L(G) = ϕ or not.

 

Algorithm-

 

  • Remove all the useless symbols from the grammar.
  • A useless symbol is one that does not derive any string of terminals.
  • If the start symbol is found to be useless, then language is empty otherwise not.

 

Remember

The language generated from a CFG is non-empty iff the start symbol is generating.

 

Example-

 

Consider the following grammar-

S → XY

X → AX

X → AA

A → a

Y → BY

Y → BB

B → b

 

Now, let us check whether language generated by this grammar is empty or not.

 

The given grammar can be written as-

S → aabb

X → aX

X → aa

A → a

Y → bY

Y → bb

B → b

 

Clearly,

  • The start symbol generates at least one string (many more are possible).
  • Therefore, start symbol is useful.
  • Thus, language generated by the given grammar is non-empty.

 

L(G) ≠ ϕ

 

NOTE-

 

If L(G) = { ∈ } i.e.

  • If the language generated by a grammar contains only a null string,
  • then it is considered as non-empty.

 

Next Article- Algorithm To Decide Whether CFL Is Finite

 

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